Differentiate the Function and Find the Slope of the Tangent$$\mathrm { s } = 2 \mathrm { t } ^ { 4 } - 2 \mathrm { t } ^ { 3 } , \mathrm { t } = - 1$$

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The Answer of Differentiate the Function and Find the Slope of the Tangent$$\mathrm { s } = 2 \mathrm { t } ^ { 4 } - 2 \mathrm { t } ^ { 3 } , \mathrm { t } = - 1$$

Differentiate the Function and Find the Slope of the Tangent $\mathrm { s } = 2 \mathrm { t } ^ { 4 } - 2 \mathrm { t } ^ { 3 } , \mathrm { t } = - 1$

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Differentiate the Function and Find the Slope of the Tangent s=2t4−2t3,t=−1\mathrm { s } = 2 \mathrm { t } ^ { 4 } - 2 \mathrm { t } ^ { 3 } , \mathrm { t } = - 1s=2t4−2t3,t=−1

Definitions:

Differentiate the Function and Find the Slope of the Tangent $\mathrm { s } = 2 \mathrm { t } ^ { 4 } - 2 \mathrm { t } ^ { 3 } , \mathrm { t } = - 1$