$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$

question 60

Multiple Choice

$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$
- $$\lim _ { x \rightarrow - 0.5 ^ { - } } \sqrt { \frac { x + 7 } { x + 5 } }$$

• A) \(\sqrt { \frac { 13 } { 9 } }\)
• B) \(\sqrt { \frac { 15 } { 11 } }\)
• C) Does not exist
• D) \(\frac { 15 } { 11 }\)

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