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 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }

question 88

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 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }
- limx1(x+3) (x+1x+1) \lim _ { x \rightarrow 1 ^ { - } } ( x + 3 ) \left( \frac { | x + 1 | } { x + 1 } \right)


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