$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$

question 35

Multiple Choice

$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$
- $\lim _{x\rightarrow\ 6^{-}}(x-\lfloor x\rfloor)$

• A) 12
• B) 6
• C) 0
• D) -12

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