Use the Table of Values of F to Estimate the Limit

question 115

Multiple Choice

Use the table of values of f to estimate the limit.
- $\text { Let } f(x) =x^{2}-5 \text {, find } \lim _{x \rightarrow \theta} f(x)$
$\begin{array}{c|c|c|c|c|c|c}\mathrm{x} & -0.1 & -0.01 & -0.001 & 0.001 & 0.01 & 0.1 \\\hline \mathrm{f}(\mathrm{x}) & & & & & &\end{array}$

• A)
• \(\begin{array}{c|llllcc}
• \mathrm{x} & -0.1 & -0.01 & -0.001 & 0.001 & 0.01 & 0.1 \\
• \mathrm{f}(\mathrm{x}) & -2.9910 & -2.9999 & -3.0000 & -3.0000 & -2.9999 & -2.9910
• \end{array} ; \text { limit }=-3.0\)
• B)
• \(\begin{array}{r|llllll}
• \mathrm{x} & -0.1 & -0.01 & -0.001 & 0.001 & 0.01 & 0.1 \\
• \hline \mathrm{f}(\mathrm{x}) & -1.4970 & -1.4999 & -1.5000 & -1.5000 & -1.4999 & -1.4970
• \end{array} \text {; limit }=-15.0\)
• C)
• \(\begin{array}{c|llllll}
• \mathrm{x} & -0.1 & -0.01 & -0.001 & 0.001 & 0.01 & 0.1 \\
• \hline \mathrm{f}(\mathrm{x}) & -1.4970 & -1.4999 & -1.5000 & -1.5000 & -1.4999 & -1.4970
• \end{array} \text { limit }=\infty\)
• D)
• \(\begin{array}{c|llllll}
• \mathrm{x} & -0.1 & -0.01 & -0.001 & 0.001 & 0.01 & 0.1 \\
• \hline \mathrm{f}(\mathrm{x}) & -4.9900 & -4.9999 & -5.0000 & -5.0000 & -4.9999 & -4.9900
• \end{array} \text {; limit }=-5.0\)

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