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 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }

question 154

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 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }
- limx2+7x25+x\lim _ { x \rightarrow 2 ^ { + } } \sqrt { \frac { 7 x ^ { 2 } } { 5 + x } }


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