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 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }

question 45

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 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }
- limh0102h2+7h+10h\lim _ { h \rightarrow 0 ^ { - } } \frac { \sqrt { 10 } - \sqrt { 2 h ^ { 2 } + 7 h + 10 } } { h }


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