$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$

question 130

Multiple Choice

$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$
- $\lim _ { x \rightarrow 0 } \frac { x ^ { 2 } - 2 x + \sin x } { x }$

• A) does not exist
• B) 0
• C) \(- 1\)
• D) 1

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