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Verify the Identity Shown Below tanα+cotβtanαcotβ=tanβ+cotα\frac { \tan \alpha + \cot \beta } { \tan \alpha \cot \beta } = \tan \beta + \cot \alpha

question 19

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Verify the identity shown below. tanα+cotβtanαcotβ=tanβ+cotα\frac { \tan \alpha + \cot \beta } { \tan \alpha \cot \beta } = \tan \beta + \cot \alpha


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