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Solve the Initial-Value Problem xyt=y+x2cosx,y(π)=0x y ^ { t } = y + x ^ { 2 } \cos x , y ( \pi ) = 0

question 28

Short Answer

Solve the initial-value problem. xyt=y+x2cosx,y(π)=0x y ^ { t } = y + x ^ { 2 } \cos x , y ( \pi ) = 0


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