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Water Flows from a Tank of Constant Cross-Sectional Area 50At250 \mathrm { At } ^ { 2 }

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Water flows from a tank of constant cross-sectional area 50At250 \mathrm { At } ^ { 2 } through an orifice of constant cross-sectional area 14ft2\frac { 1 } { 4 } \mathrm { ft } ^ { 2 } located at the bottom of the tank. Initially, the height of the water in the tank was 20ft20 \mathrm { ft } , and tt sec later it was given by the equation
2h+125t220=00t50202 \sqrt { h } + \frac { 1 } { 25 } t - 2 \sqrt { 20 } = 0 \quad 0 \leq t \leq 50 \sqrt { 20 }
How fast was the height of the water decreasing when its height was 2ft2 \mathrm { ft } ?
 Water flows from a tank of constant cross-sectional area  50 \mathrm { At } ^ { 2 }  through an orifice of constant cross-sectional area  \frac { 1 } { 4 } \mathrm { ft } ^ { 2 }  located at the bottom of the tank. Initially, the height of the water in the tank was  20 \mathrm { ft } , and  t  sec later it was given by the equation  2 \sqrt { h } + \frac { 1 } { 25 } t - 2 \sqrt { 20 } = 0 \quad 0 \leq t \leq 50 \sqrt { 20 }  How fast was the height of the water decreasing when its height was  2 \mathrm { ft }  ?    A)   \quad 100 \sqrt { 5 } - 50 \sqrt { 2 } \mathrm { ft } / \mathrm { sec }  B)   100 \sqrt { 5 } - 50 \sqrt { 2 } \mathrm { ft } / \mathrm { sec }  C)   \frac { 2 } { 25 } \mathrm { ft } / \mathrm { sec }  D)   \frac { \sqrt { 2 } } { 25 } \mathrm { ft } / \mathrm { sec }


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