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Use the Position Equation s=20t2+v0t+s0s = - 20 t ^ { 2 } + v _ { 0 } t + s _ { 0 }

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Use the position equation s=20t2+v0t+s0s = - 20 t ^ { 2 } + v _ { 0 } t + s _ { 0 } , where SS represents the height of an object (in feet) , V0\mathcal { V } _ { 0 } represents the initial velocity of the object (in feet per second) , s0s _ { 0 } represents the Initial height of the object (in feet) , and tt represents the time (in seconds) .
A projectile is fired straight upward from ground level (s0=0) \left( s _ { 0 } = 0 \right) with an initial velocity of 220220 feet Per second. At what instant will it be back at ground level?


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