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Find the Integral Using an Appropriate Trigonometric Substitution 1x2x2+36dx\int \frac { 1 } { x ^ { 2 } \sqrt { x ^ { 2 } + 36 } } d x

question 60

Short Answer

Find the integral using an appropriate trigonometric substitution.
1x2x2+36dx\int \frac { 1 } { x ^ { 2 } \sqrt { x ^ { 2 } + 36 } } d x


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