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Find an Equation of the Tangent Line to the Curve x=et,y=tlnt6;t=1x = e ^ { \sqrt { t } } , \quad y = t - \ln t ^ { 6 } ; \quad t = 1

question 107

Short Answer

Find an equation of the tangent line to the curve at the point corresponding to the value of the parameter.
x=et,y=tlnt6;t=1x = e ^ { \sqrt { t } } , \quad y = t - \ln t ^ { 6 } ; \quad t = 1


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