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Find an Equation of the Tangent to the Curve at the Point

question 83

Short Answer

Find an equation of the tangent to the curve at the point by first eliminating the parameter.
x=et,y=(t9)2;(1,81)x = e ^ { t } , \quad y = ( t - 9 ) ^ { 2 } ; \quad ( 1,81 )


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