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If a Projectile Is Fired with an Initial Velocity Of v

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If a projectile is fired with an initial velocity of v0v _ { 0 } meters per second at an angle α\alpha above the horizontal and air resistance is assumed to be negligible, then its position after tt seconds is given by the parametric equations
x=(v0cosα)t,y=(v0sinα)t12gt2x = \left( v _ { 0 } \cos \alpha \right) t , y = \left( v _ { 0 } \sin \alpha \right) t - \frac { 1 } { 2 } g t ^ { 2 }
where gg is the acceleration of gravity (9.8 m/s2)\left( 9.8 \mathrm {~m} / \mathrm { s } ^ { 2 } \right) . If a gun is fired with α=55\alpha = 55 ^ { \circ } and v0=440 m/sv _ { 0 } = 440 \mathrm {~m} / \mathrm { s } when will the bullet hit the ground?


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