Find the Values Of$p$ For Which the Series Is Convergent$$\sum _ { n = 2 } ^ { \infty } \frac { ( - 1 ) ^ { n } } { \left( \ln \left( n ^ { 6 } \right) \right) ^ { p } }$$

Question

Examlex · Accepted Answer

The Answer of Find the Values Of$p$ For Which the Series Is Convergent$$\sum _ { n = 2 } ^ { \infty } \frac { ( - 1 ) ^ { n } } { \left( \ln \left( n ^ { 6 } \right) \right) ^ { p } }$$

Find the Values Of $p$ For Which the Series Is Convergent $\sum _ { n = 2 } ^ { \infty } \frac { ( - 1 ) ^ { n } } { \left( \ln \left( n ^ { 6 } \right) \right) ^ { p } }$

Definitions:

Find the Values Of ppp For Which the Series Is Convergent ∑n=2∞(−1)n(ln⁡(n6))p\sum _ { n = 2 } ^ { \infty } \frac { ( - 1 ) ^ { n } } { \left( \ln \left( n ^ { 6 } \right) \right) ^ { p } }n=2∑∞​(ln(n6))p(−1)n​

Definitions:

Find the Values Of $p$ For Which the Series Is Convergent $\sum _ { n = 2 } ^ { \infty } \frac { ( - 1 ) ^ { n } } { \left( \ln \left( n ^ { 6 } \right) \right) ^ { p } }$