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Find the Area of the Surface z=23(x3/2+y3/2),0x3,0y3z = \frac { 2 } { 3 } \left( x ^ { 3 / 2 } + y ^ { 3 / 2 } \right) , 0 \leq x \leq 3,0 \leq y \leq 3

question 67

Short Answer

Find the area of the surface. Round your answer to three decimal places.
z=23(x3/2+y3/2),0x3,0y3z = \frac { 2 } { 3 } \left( x ^ { 3 / 2 } + y ^ { 3 / 2 } \right) , 0 \leq x \leq 3,0 \leq y \leq 3

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