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If a Projectile Is Fired with an Initial Speed Of v

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If a projectile is fired with an initial speed of v0v _ { 0 } ft/s at an angle α\alpha
Above the horizontal, then its position after t seconds is given by the parametric equations x=(v0cosα) t and y=(v0sinα) t16t2x = \left( v _ { 0 } \cos \alpha \right) t \text { and } y = \left( v _ { 0 } \sin \alpha \right) t - 16 t ^ { 2 }
Where x and y are measured in feet. Suppose a gun fires a bullet into the air with an initial speed of 1024 ft/s at an angle of 3030 ^ { \circ }
To the horizontal. How far from the gun will the bullet hit the ground?


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