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Let x=4cosθx = 4 \cos \theta 0θ<π20 \leq \theta < \frac { \pi } { 2 }

question 109

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Let x=4cosθx = 4 \cos \theta , 0θ<π20 \leq \theta < \frac { \pi } { 2 } . Simplify the expression. 4x16x2\frac { 4 x } { \sqrt { 16 - x ^ { 2 } } }

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