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Solve the Equation in the Interval [0,2π)[ 0,2 \pi ) cos2x=cosx+6\cos ^ { 2 } x = \cos x + 6

question 13

Essay

Solve the equation in the interval [0,2π)[ 0,2 \pi )
. cos2x=cosx+6\cos ^ { 2 } x = \cos x + 6


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