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Let x=2tanθx = 2 \tan \theta 0θ<π/20 \leq \theta < \pi / 2

question 41

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Let x=2tanθx = 2 \tan \theta , 0θ<π/20 \leq \theta < \pi / 2 ) Simplify the expression. 1x24+x2\frac { 1 } { x ^ { 2 } \sqrt { 4 + x ^ { 2 } } }


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