Find Pk+1 for the Given Pk $P _ { k } = \frac { k ^ { 2 } } { 6 } ( 5 k + 5 )$

question 9

Multiple Choice

Find Pk+1 for the given Pk. $P _ { k } = \frac { k ^ { 2 } } { 6 } ( 5 k + 5 )$

• A) \(P _ { k + 1 } = \frac { ( k + 1 ) ^ { 2 } } { 6 } ( 5 k + 10 )\)
• B) \(P _ { k + 1 } = \frac { k ^ { 2 } } { 6 } ( 5 k + 5 ) + 1\)
• C) \(P _ { k + 1 } = \frac { k ^ { 2 } } { 6 } ( 5 k + 10 )\)
• D) \(P _ { k + 1 } = \frac { k ^ { 2 } + 1 } { 6 } ( 5 k + 10 )\)
• E) \(P _ { k + 1 } = \frac { ( k + 1 ) ^ { 2 } } { 6 } ( 5 k + 5 )\)

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