Use the Table of Integrals to Find the Average Value $N = \frac { 330 } { 1 + e ^ { 5.7 - 0.25 t } }$

question 20

Multiple Choice

Use the table of integrals to find the average value of the growth function $N = \frac { 330 } { 1 + e ^ { 5.7 - 0.25 t } }$ over the interval $[ 22,27 ]$ , where N the size of a population and t is the time in days. Round your answer to three decimal places.

• A)200.507
• B)758.790
• C)198.507
• D)391.543
• E)321.407

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