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Set Up the Definite Integral That Gives the Area of the Region

question 17

Multiple Choice

Set up the definite integral that gives the area of the region bounded by the graphs. f(x) =(x4) 3g(x) =x4\begin{array} { l } f ( x ) = ( x - 4 ) ^ { 3 } \\g ( x ) = x - 4\end{array}  Set up the definite integral that gives the area of the region bounded by the graphs.  \begin{array} { l }  f ( x )  = ( x - 4 )  ^ { 3 } \\ g ( x )  = x - 4 \end{array}    A)   \int _ { 3 } ^ { 4 } \left( ( x - 4 )  - ( x - 4 )  ^ { 3 } \right)  d x + \int _ { 4 } ^ { 5 } \left( ( x - 4 )  ^ { 3 } - ( x - 4 )  \right)  d x  B)   \int _ { - 1 } ^ { 0 } \left( ( x - 4 )  + ( x - 4 )  ^ { 3 } \right)  d x + \int _ { 0 } ^ { 1 } \left( ( x - 4 )  ^ { 3 } + ( x - 4 )  \right)  d x  C)   \int _ { - 1 } ^ { 0 } \left( ( x - 4 )  ^ { 3 } - ( x - 4 )  \right)  d x + \int _ { 0 } ^ { 1 } \left( ( x - 4 )  - ( x - 4 )  ^ { 3 } \right)  d x  D)   \int _ { 3 } ^ { 4 } \left( ( x - 4 )  ^ { 3 } - ( x - 4 )  \right)  d x + \int _ { 4 } ^ { 5 } \left( ( x - 4 )  - ( x - 4 )  ^ { 3 } \right)  d x  E)   \int _ { 3 } ^ { 4 } \left( ( x - 4 )  ^ { 3 } + ( x - 4 )  \right)  d x + \int _ { 4 } ^ { 5 } \left( ( x - 4 )  + ( x - 4 )  ^ { 3 } \right)  d x


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