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After T Years, the Remaining Mass Y(in Grams) of 16 y=16(12)t/32y = 16 \left( \frac { 1 } { 2 } \right) ^ { t / 32 }

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After t years, the remaining mass y(in grams) of 16 grams of a radioactive element whose half-life is 32 years is given by y=16(12) t/32y = 16 \left( \frac { 1 } { 2 } \right) ^ { t / 32 } , for t0t \geq 0 . How much of the initial mass remains after 96 years? Round your answer to two decimal places.


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