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The Area of a Triangle with Vertices (x1,y1),\left( x _ { 1 } , y _ { 1 } \right),

question 21

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The area of a triangle with vertices (x1,y1) ,\left( x _ { 1 } , y _ { 1 } \right) , (x2,y2) ,\left( x _ { 2 } , y _ { 2 } \right) , and (x3,y3) \left( x _ { 3 } , y _ { 3 } \right) can be given as the absolute value of the determinant 12x1y11x2y21x3y31\frac { 1 } { 2 } \left| \begin{array} { l l l } x _ { 1 } & y _ { 1 } & 1 \\x _ { 2 } & y _ { 2 } & 1 \\x _ { 3 } & y _ { 3 } & 1\end{array} \right| Use this formula to find the area of each triangle whose coordinates are (6,2) ,( - 6,2 ) , (0,3) ,( 0,3 ) , and (5,6) .( - 5,6 ) .


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