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The Height in Feet of a Projectile with an Initial h(t)=16t2+128t+50.h ( t ) = - 16 t ^ { 2 } + 128 t + 50.

question 41

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The height in feet of a projectile with an initial velocity of 128 feet per second and an initial height of 50 feet is a function of time t, in seconds, given by h(t) =16t2+128t+50.h ( t ) = - 16 t ^ { 2 } + 128 t + 50. Find the maximum height of the projectile.

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