Solve $\frac { 1 } { x - 6 } + \frac { 2 } { x + 2 } = \frac { 3 } { x ^ { 2 } - 4 x - 12 }$

question 36

Multiple Choice

Solve: $\frac { 1 } { x - 6 } + \frac { 2 } { x + 2 } = \frac { 3 } { x ^ { 2 } - 4 x - 12 }$

• A) \(x = \frac { 7 } { 3 }\)
• B) \(x = - \frac { 4 } { 3 }\)
• C) \(x = - \frac { 5 } { 3 }\)
• D) \(x = \frac { 13 } { 3 }\)
• E) \(x = \frac { 1 } { 3 }\)

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