Voltage Across a Capacitor with Capacitance of 39 Is Given$\mu \mathrm { F }$

Question

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The Answer is

i ( t ) = \left\{ \begin{array} { c } - 1.17 , \quad 0 \leq t < 5 \3.51 , \quad 5 \leq t < 10 \- 2.34 , \quad 10 \leq t < 15 \0 , ext { elsewhere }\end{array} \quad \mathrm { mA } ight.

$i ( t ) = \left\{ \begin{array} { c } - 1.17 , \quad 0 \leq t < 5 \ 3.51 , \quad 5 \leq t < 10 \ - 2.34 , \quad 10 \leq t < 15 \ 0 , ext { elsewhere } \end{array} \quad \mathrm { mA } ight.$

Voltage Across a Capacitor with Capacitance of 39 Is Given $\mu \mathrm { F }$

Definitions:

Voltage Across a Capacitor with Capacitance of 39 Is Given μF\mu \mathrm { F }μF

Definitions:

Voltage Across a Capacitor with Capacitance of 39 Is Given $\mu \mathrm { F }$