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Solve the Problem d=L2+W2+H2,\mathrm { d } = \sqrt { \mathrm { L } ^ { 2 } + \mathrm { W } ^ { 2 } + \mathrm { H } ^ { 2 } } ,

question 112

Multiple Choice

Solve the problem.
-A formula for the length of a diagonal from the upper corner of a box to the opposite lower corner is d=L2+W2+H2,\mathrm { d } = \sqrt { \mathrm { L } ^ { 2 } + \mathrm { W } ^ { 2 } + \mathrm { H } ^ { 2 } } , where L, W, and H are the length, width, and height, respectively. Find the length of t where L, W, and H are the length, width, and height, respectively. Find the length of the diagonal of the box if the length is 22 inches, width is 15 inches, and height is 6 inches. Leave your answer in
Simplified radical form.  Solve the problem. -A formula for the length of a diagonal from the upper corner of a box to the opposite lower corner is  \mathrm { d } = \sqrt { \mathrm { L } ^ { 2 } + \mathrm { W } ^ { 2 } + \mathrm { H } ^ { 2 } } ,  where L, W, and H are the length, width, and height, respectively. Find the length of t where L, W, and H are the length, width, and height, respectively. Find the length of the diagonal of the box if the length is 22 inches, width is 15 inches, and height is 6 inches. Leave your answer in Simplified radical form.   A)   \sqrt { 86 } \mathrm { ~in. }  B)   \sqrt { 43 } \text { in. }  C)   \sqrt { 745 } \text { in. }  D)   \sqrt { 1490 } \text { in. }


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