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Solve the Problem v=2gh,\mathrm { v } = \sqrt { 2 \mathrm { gh } },

question 252

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Solve the problem.
-A formula used to determine the velocity v in feet per second per second of an object (neglecting air resistance) after it has fallen a certain height iss v v=2gh,\mathrm { v } = \sqrt { 2 \mathrm { gh } }, , where g is the acceler where g is the acceleation due to gravity and h is the height the
Object has fallen. If the acceleration g due to gravity on Earth is approximately 32 feet per second per second,
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