Solve the System Using Determinants$$\begin{array} { l }
3 x + y + \frac { 3 } { 2 } z = - 11 \
\frac { 1 } { 2 } x + 3 z = 10 \
x 4 y = - 24
\end{array}$$

Question

Solve the System Using Determinants$$\begin{array} { l } 
3 x + y + \frac { 3 } { 2 } z = - 11 \
\frac { 1 } { 2 } x + 3 z = 10 \
x 4 y = - 24
\end{array}$$

Examlex · Accepted Answer

The Answer of Solve the System Using Determinants$$\begin{array} { l } 
3 x + y + \frac { 3 } { 2 } z = - 11 \
\frac { 1 } { 2 } x + 3 z = 10 \
x 4 y = - 24
\end{array}$$

Solve the System Using Determinants $\begin{array} { l } 3 x + y + \frac { 3 } { 2 } z = - 11 \\\frac { 1 } { 2 } x + 3 z = 10 \\x 4 y = - 24\end{array}$

Definitions:

Solve the System Using Determinants 3x+y+32z=−1112x+3z=10x4y=−24\begin{array} { l } 3 x + y + \frac { 3 } { 2 } z = - 11 \\\frac { 1 } { 2 } x + 3 z = 10 \\x 4 y = - 24\end{array}3x+y+23​z=−1121​x+3z=10x4y=−24​

Definitions:

Solve the System Using Determinants $\begin{array} { l } 3 x + y + \frac { 3 } { 2 } z = - 11 \\\frac { 1 } { 2 } x + 3 z = 10 \\x 4 y = - 24\end{array}$