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A current is passed through a molten mixture of ZnI2 and KCl. Given the half reactions shown below, the product at the cathode is:
K+ + e - →K E ° = - 2.92 V Zn2+ + 2 e - →Zn E ° = - 0.76 V I2 + 2 e - →2 I - E ° = +0.535 V Cl2 + 2 e - →2 Cl - E ° = +1.36 V
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