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The Nuclide 226 Ra Undergoes a Series of Alpha and Beta

question 76

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The nuclide 226 Ra undergoes a series of alpha and beta decays, finally producing the stable nuclide 206 Pb. The nuclide 226 Ra undergoes a series of alpha and beta decays, finally producing the stable nuclide 206 Pb.     + A   + B   What are the values of A and B in the equation? A)  A = 6, B = 10 B)  A = 5, B = 4 C)  A = 4, B = 5 D)  A = 10, B = 6 E)  none of these The nuclide 226 Ra undergoes a series of alpha and beta decays, finally producing the stable nuclide 206 Pb.     + A   + B   What are the values of A and B in the equation? A)  A = 6, B = 10 B)  A = 5, B = 4 C)  A = 4, B = 5 D)  A = 10, B = 6 E)  none of these + A The nuclide 226 Ra undergoes a series of alpha and beta decays, finally producing the stable nuclide 206 Pb.     + A   + B   What are the values of A and B in the equation? A)  A = 6, B = 10 B)  A = 5, B = 4 C)  A = 4, B = 5 D)  A = 10, B = 6 E)  none of these + B The nuclide 226 Ra undergoes a series of alpha and beta decays, finally producing the stable nuclide 206 Pb.     + A   + B   What are the values of A and B in the equation? A)  A = 6, B = 10 B)  A = 5, B = 4 C)  A = 4, B = 5 D)  A = 10, B = 6 E)  none of these What are the values of A and B in the equation?


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