Use Cramer S Rule to Solve the System for Z $\left\{ \begin{array} { l } x + y - z = 4 \\8 x - 6 y + 7 z = 1 \\x + 9 y - z = - 2\end{array} \right.$

question 214

Multiple Choice

Use Cramer s Rule to solve the system for z. $\left\{ \begin{array} { l } x + y - z = 4 \\8 x - 6 y + 7 z = 1 \\x + 9 y - z = - 2\end{array} \right.$

• A) \(z = \frac { \left| \begin{array} { c c c }
• 4 & 1 & - 1 \\
• 1 & - 6 & 7 \\
• - 2 & 9 & - 1
• \end{array} \right| } { \left| \begin{array} { c c c }
• 1 & 1 & - 1 \\
• 8 & - 6 & 7 \\
• 1 & 9 & - 1
• \end{array} \right| }\)
• B) \(z = \frac { \left| \begin{array} { c c c }
• 1 & 1 & 4 \\
• 8 & - 6 & 1 \\
• 1 & 9 & - 2
• \end{array} \right| } { \left| \begin{array} { c c c }
• 1 & 1 & - 1 \\
• 8 & - 6 & 7 \\
• 1 & 9 & - 1
• \end{array} \right| }\)
• C) \(z = \frac { \left| \begin{array} { c c c }
• 1 & 4 & - 1 \\
• 8 & 1 & 7 \\
• 1 & 9 & - 2
• \end{array} \right| } { \left| \begin{array} { c c c }
• 1 & 1 & - 1 \\
• 8 & - 6 & 7 \\
• 1 & 9 & - 1
• \end{array} \right| }\)
• D) \(z = \frac { \left| \begin{array} { c c c }
• 1 & 1 & - 1 \\
• 8 & - 6 & 7 \\
• 1 & 9 & - 1
• \end{array} \right| } { \left| \begin{array} { c c c }
• 1 & 1 & 4 \\
• 8 & - 6 & 1 \\
• 1 & 9 & - 2
• \end{array} \right| }\)

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