The Receipts for One Showing of a Movie Were $808 $\left\{ \begin{array} { l } x + y + z = 110 \\6 x + 8 y + 7 z = 808 \\y = 2 x\end{array} \right.$

question 148

Multiple Choice

The receipts for one showing of a movie were $808 for an audience of 110 people. Children's tickets are $6, general admission is $8, and tickets for seniors are $7. Twice as many general admission tickets as children's tickets were purchased. If x is the number of children's tickets purchased, y is the number of general admissions tickets purchased, and z is the number of senior tickets purchased, write a system of three equations in three variables that models the situation.

• A) \(\left\{ \begin{array} { l }
• x + y + z = 110 \\
• 6 x + 8 y + 7 z = 808 \\
• y = 2 x
• \end{array} \right.\)
• B) \(\left\{ \begin{array} { l }
• x + y + z = 110 \\
• 6 x + 8 y + 7 z = 808 \\
• x = 2 y
• \end{array} \right.\)
• C) \(\left\{ \begin{array} { l }
• x + y + z = 808 \\
• 6 x + 8 y + 7 z = 110 \\
• y = 2 x
• \end{array} \right.\)
• D) \(\left\{ \begin{array} { l }
• x + y + z = 808 \\
• 6 x + 8 y + 7 z = 110 \\
• x = 2 y
• \end{array} \right.\)

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