Solve $d = \frac { 4 c b } { b + c }$

question 140

Multiple Choice

Solve $d = \frac { 4 c b } { b + c }$ for b.

• A) \(b = \frac { c d } { 4 c - 1 }\)
• B) \(b = \frac { 1 } { 4 }\)
• C) \(b = \frac { d ( b + c ) } { 4 c }\)
• D) \(b = \frac { c d } { 4 c - d }\)

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