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Solve Graphically 16Ω16 \Omega Their Difference Is 2Ω2 \Omega Find the Two Resistances

question 58

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Solve graphically. The sum of two resistances is 16Ω16 \Omega . Their difference is 2Ω2 \Omega . Find the two resistances. If we let R1R _ { 1 } and R2R _ { 2 } be the two resistances, the equations are R1+R2=16R1R2=2\begin{array} { l } R _ { 1 } + R _ { 2 } = 16 \\R _ { 1 } - R _ { 2 } = 2\end{array}


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