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Solve Graphically 3i1+4i2=415i12i2=25\begin{array} { l } 3 i _ { 1 } + 4 i _ { 2 } = 41 \\5 i _ { 1 } - 2 i _ { 2 } = 25\end{array}

question 94

Multiple Choice

Solve graphically. An electric circuit containing two currents may be expressed by the equation 3i1+4i2=415i12i2=25\begin{array} { l } 3 i _ { 1 } + 4 i _ { 2 } = 41 \\5 i _ { 1 } - 2 i _ { 2 } = 25\end{array} where i 1 and i 2 are the currents in microamperes ( μA\mu A ) . Find the two currents.


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