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Solve the System by Using the Substitution Method (4x+y=405xy=41)\left( \begin{array} { c } 4 x + y = 40 \\5 x - y = 41\end{array} \right)

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Solve the system by using the substitution method. (4x+y=405xy=41)\left( \begin{array} { c } 4 x + y = 40 \\5 x - y = 41\end{array} \right) Please enter your answer as an ordered pair in the form ( x , y ).


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