If $f ( x ) = \frac { 2 } { x - 5 }$

question 179

Multiple Choice

If $f ( x ) = \frac { 2 } { x - 5 }$ find $f ( - 5 ) , f ( 0 ) , f ( 5 ) , f ( - 3 )$ .

• A) \(f ( - 5 ) = - \frac { 1 } { 5 } , f ( 0 ) = - \frac { 2 } { 5 } , f ( 5 ) \text { does not exist, } f ( - 3 ) = - \frac { 1 } { 4 }\)
• B) \(f ( - 5 ) \text { does not exist, } f ( 0 ) = - \frac { 2 } { 5 } , f ( 5 ) = \frac { 1 } { 5 } , f ( - 3 ) = - \frac { 1 } { 4 }\)
• C) \(f ( - 5 ) = \frac { 1 } { 5 } , f ( 0 ) = - \frac { 2 } { 5 } , f ( 5 ) \text { does not exist, } f ( - 3 ) = - \frac { 1 } { 4 }\)
• D) \(f ( - 5 ) = - \frac { 1 } { 5 } , f ( 0 ) = - \frac { 2 } { 5 } , f ( 5 ) = \frac { 1 } { 5 } , f ( - 3 ) = \frac { 1 } { 4 }\)

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