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To Solve the System (2xy+3z=52y+z=34z=8)\left( \begin{array} { r } 2 x - y + 3 z = 5 \\2 y + z = 3 \\4 z = 8\end{array} \right)

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To solve the system (2xy+3z=52y+z=34z=8)\left( \begin{array} { r } 2 x - y + 3 z = 5 \\2 y + z = 3 \\4 z = 8\end{array} \right) , solve the equation 4z=84 z = 8 first.


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