How Does$\frac{4 x-16}{x^{2}+4 x-12}$ Resolve into Partial Fractions?
A)$\frac{-1}{x-2}+\frac{-5}{x+6}$ B)$\frac{1}{x-2}+\frac{-5}{x+6}$

Question

How Does$\frac{4 x-16}{x^{2}+4 x-12}$ Resolve into Partial Fractions? 
A)$\frac{-1}{x-2}+\frac{-5}{x+6}$ B)$\frac{1}{x-2}+\frac{-5}{x+6}$

Examlex · Accepted Answer

The Answer of How Does$\frac{4 x-16}{x^{2}+4 x-12}$ Resolve into Partial Fractions? 
A)$\frac{-1}{x-2}+\frac{-5}{x+6}$ B)$\frac{1}{x-2}+\frac{-5}{x+6}$

How Does $\frac{4 x-16}{x^{2}+4 x-12}$ Resolve into Partial Fractions?
A) $\frac{-1}{x-2}+\frac{-5}{x+6}$ B) $\frac{1}{x-2}+\frac{-5}{x+6}$

Definitions:

How Does 4x−16x2+4x−12\frac{4 x-16}{x^{2}+4 x-12}x2+4x−124x−16​ Resolve into Partial Fractions? A) −1x−2+−5x+6\frac{-1}{x-2}+\frac{-5}{x+6}x−2−1​+x+6−5​ B) 1x−2+−5x+6\frac{1}{x-2}+\frac{-5}{x+6}x−21​+x+6−5​

Definitions:

How Does $\frac{4 x-16}{x^{2}+4 x-12}$ Resolve into Partial Fractions?
A) $\frac{-1}{x-2}+\frac{-5}{x+6}$ B) $\frac{1}{x-2}+\frac{-5}{x+6}$