Given the Following Code, What Will Happen If the Value $\quad$

question 2

Multiple Choice

Given the following code, what will happen if the value of denom is 0?
double divide(int numer, int denom)
{
if (denom == 0)
$\quad$ throw "ERROR: Cannot divide by zero.\n";
else
$\quad$ Return static_cast<double>(numer) /denom;
}

• A) Nothing will happen because there is no catch block.
• B) The program will display ERROR: Cannot divide by zero.and then move to the statement following the if/else block.
• C) The program will display ERROR: Cannot divide by zero.and then halt.
• D) There is no throw point because there is no try block.
• E) None of these

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