NADH + H⁺ Has More Reducing Power Than FADH₂, Therefore $\Delta$

question 56

Multiple Choice

NADH + H⁺ has more reducing power than FADH₂, therefore:

• A) oxidation of NADH will contribute to form a larger \(\Delta\)p and more ATP
• B) oxidation of FADH₂ by respiratory ETS contributes less to \(\Delta\)p formation, and as a consequence fewer ATP can be made
• C) the NADH + H⁺/NAD⁺ redox pair has a more negative E°' value than the FAD/FADH₂ pair
• D) all of the above
• E) none of the above

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