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Consider the following balanced reaction. How many grams of water are required to form 75.9 g of HNO3? Assume that there is excess NO2 present. The molar masses are as follows:
H2O = 18.02 g mol-1, HNO3 = 63.02 g mol-1. 3NO2(g) + H2O(l) → 2HNO3(aq) + NO(g)
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