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Use the standard reaction enthalpies given below to determine ΔrH° for the following reaction: P4(g) + 10Cl2(g) → 4PCl5(s) ΔrH° = ?
Given:
PCl5(s) → PCl3(g) + Cl2(g) ΔrH°= +157 kJ
P4(g) + 6Cl2(g) → 4PCl3(g) ΔrH° = -1207 kJ
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