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Calculate [Ba2+] When 35

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Calculate [Ba2+] when 35.00 mL of 0.2000 M EDTA is added to 50.00 mL of 0.1000 M Ba2+ in the presence of 0.1 M nitrilotriacetate. Calculate [Ba<sup>2+</sup>] when 35.00 mL of 0.2000 M EDTA is added to 50.00 mL of 0.1000 M Ba<sup>2+</sup> in the presence of 0.1 M nitrilotriacetate.   = 1.48 x 10<sup>−</sup><sup>4</sup>.   = 0.30 for pH 10.K<sub>f</sub> = 7.59 × 10<sup>7</sup> for BaY<sup>2</sup><sup>−</sup>. = 1.48 x 104. Calculate [Ba<sup>2+</sup>] when 35.00 mL of 0.2000 M EDTA is added to 50.00 mL of 0.1000 M Ba<sup>2+</sup> in the presence of 0.1 M nitrilotriacetate.   = 1.48 x 10<sup>−</sup><sup>4</sup>.   = 0.30 for pH 10.K<sub>f</sub> = 7.59 × 10<sup>7</sup> for BaY<sup>2</sup><sup>−</sup>. = 0.30 for pH 10.Kf = 7.59 × 107 for BaY2.


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