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A Stationary Plutonium-239 Nucleus Decays into a Uranium-235 Nucleus Plus

question 47

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A stationary plutonium-239 nucleus decays into a uranium-235 nucleus plus an alpha particle. The energy released in the process is 5.24 MeV. Given the following mass values: A stationary plutonium-239 nucleus decays into a uranium-235 nucleus plus an alpha particle. The energy released in the process is 5.24 MeV. Given the following mass values: , 4.002603 u; , 235.043924 u; what is the kinetic energy of the nucleus? 1 u =931.494 MeV/c<sup>2</sup>. A) 0.0829 MeV B) 0.0837 MeV C) 0.0852 MeV D) 0.0863 MeV E) 0.0877 MeV , 4.002603 u; A stationary plutonium-239 nucleus decays into a uranium-235 nucleus plus an alpha particle. The energy released in the process is 5.24 MeV. Given the following mass values: , 4.002603 u; , 235.043924 u; what is the kinetic energy of the nucleus? 1 u =931.494 MeV/c<sup>2</sup>. A) 0.0829 MeV B) 0.0837 MeV C) 0.0852 MeV D) 0.0863 MeV E) 0.0877 MeV , 235.043924 u; what is the kinetic energy of the A stationary plutonium-239 nucleus decays into a uranium-235 nucleus plus an alpha particle. The energy released in the process is 5.24 MeV. Given the following mass values: , 4.002603 u; , 235.043924 u; what is the kinetic energy of the nucleus? 1 u =931.494 MeV/c<sup>2</sup>. A) 0.0829 MeV B) 0.0837 MeV C) 0.0852 MeV D) 0.0863 MeV E) 0.0877 MeV nucleus?
1 u =931.494 MeV/c2.

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